Norton's Theorem Circuit
Norton's Theorem Circuit: We have the following values: Norton Current (I_N) = 6 A Load Resistance (R_L) = 6 Ω Norton Resistance (R_N) = 3 Ω Calculate the…
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Norton's Theorem Circuit:
We have the following values:
Norton Current (I_N) = 6 A
Load Resistance (R_L) = 6 Ω
Norton Resistance (R_N) = 3 Ω
Calculate the Load Current (I_L)
We use the formula for I_L:
I_L = I_N × (R_L / (R_N + R_L))
Substitute the values:
I_L = 6 A × (6 Ω / (3 Ω + 6 Ω))
Simplify:
I_L = 6 × (6 / 9)
What's inside
- 1× Power Source
- 2× Resistor (3 Ω, 6 Ω)
- Measured with Voltmeter/Ammeter
